The if() statement tests for a boolean (true or false) condition, and executes the following code accordingly. The condition that falls within the parentheses is the boolean condition that determines which code path your program will take. But what exactly can go inside the inside the parentheses? As it turns out, any operator-based expression can be used:

**The double-equals (==):**The double-equals is used for comparison (x==5 is logically the same as “x is equal in value to 5”, while the single equals, x=5,*assigns*the value of 5 to the variable*x*). This can be used to test for the result of an expression:`if(x % 2 == 0) // If x is even NSLog(@"x is even."); else NSLog(@"x is odd.");`

Make sure that you use the double equals for a comparison; a single equals is only used for assignment, and unless you are assigning zero to a variable, the expression will always be true (because any non-zero expression is considered true).

**The not equal to (!=):**The*not equal to*operator is the exact opposite of the double-equals; if the left part is not equal to the right, then execute the following code.`if (x != 5) NSLog(@"x does not equal 5.");`

**The Greater-than, Less-than (<, >, <=, >=):**These operators work just like they do in real life. They are the*less than*,*greater than*,*less than or equal to*, and*greater than or equal to*operators, which have not changed since high-school algebra.`if (x > 5) NSLog(@"x is greater than 5."); else if (x < 5) NSLog(@"x is less than 5."); else NSLog(@"x is equal to 5.");`

**Boolean Operators (&&, ||, !):**Three symbols (or pairs of symbols) can also be used to express a boolean condition. These are the*and*(&&), the*or*(||), and the*not*(!). These are just as logical as the if() statement itself:`if ((x >= 5) && (y < 10)) NSLog(@"x is greater than or equal to 5, AND y is less than 10."); if (x == 3 || y == 6) NSLog(@"x is equal to 3 OR y is equal to 6"); if (!(x > 2 && y < 5)) NSLog(@"x is NOT greater than 2 AND y is NOT less than 5");`

See also this excellent document on Scribd, and of the course the Wikipedia entry for a more technical description of what can be achieved with boolean operators.

When using these expressions in conjunction, don’t hesitate to use parentheses or spaces to make your purpose clear. Although the operator precedence table tells us that the internal parentheses were not needed in the last example, their presence helps clarify the logical intent.

By the way, the Conditional Operator is an oddity (among operators) that could save you a bit of typing:

https://cupsofcocoa.wordpress.com/2010/10/26/oddities-conditional-operator/

## Connor

/ March 24, 2012GNUstep shell says error expected identifier of ‘(‘ before ‘{‘ token.

X is undeclared

Cannot find interface declaration for NXConstantString.

What is the problem.

#import

int main(int argc, const char *argv[]){

int result;

result = 45 * 89;

printf(“Hello World, Hello World!\n Hello\nThe product of 45 and 89 is %i”,result);

result = 14 – 2 * 3 + 4 * 5;

printf(“\n The answer to 14 – 2 * 3 + 4 *5 is %i”, result);

int a = 45;

int b = 2;

result = a * b;

printf(“\n The answer to a * b, if a = 45 and b = 2 is %i”, result);

if (x > 5)

NSLog(@”x is greater than 5.”);

else if (x < 5)

NSLog(@"x is less than 5.");

else

NSLog(@"x is equal to 5.");

return 0;

}

## inspire48

/ March 24, 2012The issue is with the block of if() statements you have at the bottom. You have to declare x, just like you did with result, a, and b. For example:

int x = 6;

if (x > 5)

NSLog(@”x is greater than 5.”);

else if (x < 5)

NSLog(@"x is less than 5.");

else

NSLog(@"x is equal to 5.");

## Connor

/ March 24, 2012GNUstep compiler still says “cannot find interface declaration for NXContantString “

## inspire48

/ March 24, 2012Make sure your import line is correct:

#import

If you’re still getting the issue, try this StackOverflow link:

http://stackoverflow.com/questions/4976351/nslog-error-cant-find-nxconstantstring